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$\{x \in R : \cos 2 x + 2 \cos^{2} x = 2\}$ is equal to

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\{2 n π + \frac{π}{3} : n \in Z\}

\{n π \pm \frac{π}{6} : n \in Z\}

\{n π + \frac{π}{3} : n \in Z\}

\{2 n π - \frac{π}{3} : n \in Z\}

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detailed solution

Correct option is B

We have

$\begin{array}{l} \cos 2 x + 2 \cos^{2} x = 2 \\ \Rightarrow 4 \cos^{2} x = 3 \Rightarrow \cos^{2} x = \cos^{2} \frac{π}{6} \Rightarrow x = n π \pm \frac{π}{6}, n \in Z \end{array}$

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x∈R:cos⁡2x+2cos2⁡x=2 is equal to

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$\{x \in R : \cos 2 x + 2 \cos^{2} x = 2\}$ is equal to