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$X Y_{2}$ dissociates $X Y_{2} (g) ⇌ X Y (g) + Y (g)$ .When the initial pressure of $X Y_{2}$ is 600mm Hg, the total equilibrium pressure is 800 mm Hg.Calculate K for the reaction .Assuming that the volume of the system remains unchanged

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166.6

50.0

400.0

100.0

answer is B.

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Detailed Solution

$\begin{matrix} X Y_{2} ⇌ X Y + Y \end{matrix}$

Initial P 0 0

Final P-x x x

Initial P=600 mm Hg.Final P=800 mmHg

Total mole $\propto$ final P

P-x+x+x $\propto$ 800

600-x+x+x $\propto$ 800

x = 200 mm Hg

$\propto K = \frac{x \times x}{P - x} = \frac{200 \times 200}{400} = 100 H g$

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