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${XY}_{2}$ dissociates as: ${XY}_{2 (g)} ⇌ XY (g) + Y (g)$ .Initial pressure of ${XY}_{2}$ is 600 mm Hg. The total pressure at equilibrium is 800 mm Hg. Assuming volume of system to remain constant, the value of Kp is

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100

400

200

answer is B.

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Detailed Solution

${XY}_{2 (g)} ⇌ XY (g) + Y (g)$

600mm 0 0

600 - x x x

600 - x+ x + x = 800

x=200

400 200 200

$K_{P} = \frac{200 \times 200}{400} = 100 mm$

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