Q.

XY2dissociates as: XY2(g)XY(g)+Y(g).Initial pressure ofXY2 is 600 mm Hg. The total pressure at equilibrium is 800 mm Hg. Assuming volume of system to remain constant, the value of Kp is

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a

100

b

400

c

50

d

200

answer is B.

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Detailed Solution

XY2(g)XY(g)+Y(g)

600mm          0           0 

600 - x              x           x  

600 - x+ x + x = 800

x=200

400           200                  200

KP=200×200400=100 mm            

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