Y-component of velocity is 20 and X-component of velocity is 10. The direction of motion of the body with the horizontal at this instant is

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$\tan^{- 1} (2)$

$\tan^{- 1} (1 / 2)$

$45^{\circ}$

$0^{\circ}$

answer is A.

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Detailed Solution

We know that

$\begin{array}{l} \tan θ = \frac{vertical component of velocity}{horizontal component of velocity} \\ = \frac{V_{y}}{V_{x}} \\ or \tan θ = \frac{20}{10} = 2 or θ = \tan^{- 1} (2) \end{array}$

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