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$Y \overset{}{\overset{Na}{\leftarrow}} X \overset{}{\overset{Conc . H_{2} {SO}_{4} / 413 K}{\to}} {(C_{2} H_{5})}_{2} O$
What are X and Y in the above reactions ?

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X Y
$H_{3} COH$ $H_{3} CONa$

X Y
$C_{2} H_{5} OH$ $C_{2} H_{5} ONa$

X Y
$C_{3} H_{2} OH$ $C_{3} H_{7} ONa$

X Y
$C_{4} H_{9} OH$ $C_{4} H_{9} ONa$

answer is C.

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