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Young’s double slit experiment is performed using light of wavelength 600 nm. When a mica film of refractive index 1.6 and thickness t is introduced in the path of one of the interfering beams, the intensity of light at the position where the central bright fringe previously appeared remains unchanged. The minimum thickness of the mica film is

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$10^{- 6} m$

$10^{- 3} m$

$10^{- 4} m$

$1 m m$

answer is A.

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Detailed Solution

$s h i f t = \frac{β}{λ} (μ - 1) t$

$n β = \frac{β}{λ} (μ - 1) t$

for n=1

$t = \frac{λ}{μ - 1} = \frac{600 \times 10^{- 9}}{1.6 - 1} = 10^{- 6} m$

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