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Q.

Youngs double slit experiment the distance between slit and the screen is 1.2 m and the distance between the two slits is 24 mm. If a thin transparent mica sheet of thickness 1 $μ$ m and Retractive Index 1.5 is introduced between one of the interfering beam, the shift in the position of central bright fringe is.

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a

0.5 mm

b

0.25 mm

c

0.125 mm

d

2 mm

answer is B.

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Detailed Solution

Given data D=1.2m , d=2.4mm, thickness $t = 1 \times 10^{- 6}, μ = 1.5$
Shift in the image pattern
$\begin{array}{l} Δ y = \frac{D}{d} (μ - 1) t \\ = \frac{1.2}{24 \times 10^{- 3}} (1.5 - 1) 1 \times 10^{- 6} \\ = 0.25 \times 10^{- 3} m = 0.25 m m \end{array}$

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