Q.

Young's modulus of rubber is  104N/m2 and area of cross-section is 2cm2 . If force of 2×105 dynes is applied along its length, then its initial length l  becomes 

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

4L

b

3L

c

2L

d

None of the above

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Y=104N/m2,A=2×104m2,F=2×105 dyne =2Nl=FLAY=2×L2×104×104=L

 Final length = initial length + increment = 2L

Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
Young's modulus of rubber is  104 N/m2 and area of cross-section is 2 cm2 . If force of 2×105 dynes is applied along its length, then its initial length l  becomes