(Z)-2-Butene reacts with Br₂/H₂O. The resulting bromohydrin when treated with methoxide in methanol undergoes an intramolecular ${\mathrm{S}}_{{\mathrm{N}}^2}$ reaction. Taking into consideration the stereochemical consequences of the reaction mechanism involved, choose the final product(s) of these transformations.

Bromohydrin Formation and Intramolecular SN2 Reaction

When (Z)-2-butene reacts with Br₂/H₂O, it forms bromohydrins with anti stereochemistry, where the bromine and hydroxyl groups add across the double bond in a trans manner.

These bromohydrins, upon treatment with sodium methoxide (NaOMe) in methanol, undergo an intramolecular S_N2 reaction. The hydroxyl group attacks the adjacent carbon bearing bromine, displacing it via backside attack, leading to inversion of configuration at that carbon.

As a result, two enantiomeric epoxides are formed, specifically (2R,3R)-2,3-epoxybutane and (2S,3S)-2,3-epoxybutane.

This mechanism explains how stereochemical details of the reaction influence the final products, resulting from anti addition followed by intramolecular nucleophilic substitution with inversion.