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Q.

 z=i1cosπ3+isinπ3 is equal to

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a

2 cos5π12+isin5π12

b

cosπ12isinπ12

c

2cosπ12+isinπ12

d

2  cos5π12isin5π12

answer is A.

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Detailed Solution

z=i1cosπ3+isinπ3=-1+icosπ3+isinπ3

z=2cis3π4cisπ3=2cis3π4-π3=2cis5π12

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 z=i−1cosπ3+isinπ3 is equal to