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Q.

z1,z2,z3  are three non-zero distinct affixes satisfying  |z1|=1&z22=z1z3 then

(Note : arg (z) represents principle argument of z;   
arg(z)(π,π]

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a

z3z2z2+z32  is purely imaginary

b

arg(z21z11)=2arg(z3z2)

c

arg(z21z11)=2arg(z3z1)

d

|1z21z3|+|1z11z2|=|1z11z3|

answer is A, B, D.

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Detailed Solution

1st option – chord  (Z3Z2) is   to line joining   z2+z32and 1.
 Question Image
2nd option – angle by chord  (Z3Z2) at (1,0)  is double of angle at  (0,0)
4th option – Ptolemy’s theorem

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