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Q.

z1+z22=z12+z22 where z1z2 are two complex numbers then

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a

z1z2  is purely real 

b

z1z2  is purely Imaginary

c

arg z1z2=π4

d

z1z2=1

answer is B.

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Detailed Solution

z1=x+iy  z2=a+ib

z1+z22=z12+z22

x+a2+y+b2=x2+y2+a2+b2

ax+by=0

z1z2=ax+bya2+b2+aybxa2+b2i

=aybxa2+b2i

Purely imaginary

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