Z/e ratio for $N^{3-}$, $O^{2-}$ and $F^{-}$ respectively will be:

Z/e ratio for $N^{3-}$, $O^{2-}$ and $F^{-}$ respectively will be: 0.7, 0.8 and 0.9.

The ratio of the atomic number "Z" and the number of electrons "n" in the ionic species is what determines the radii of these species, which is known as the Z/e ratio.

Hence, option A is correct.