Zinc reacts with CuSO₄ according to the equation Zn + CuSO₄ → ZnSO₄ + Cu. If excess of zinc is added to 100ml of 0.05M CuSO₄, the amount of copper formed

Given,

$$\begin{gathered} \mathrm{Zn} + {\mathrm{CuSO}}_4 \to {\mathrm{ZnSO}}_4 + \mathrm{Cu}. \\ 1\mathrm{mol} 1\mathrm{mol} \\ 100\mathrm{ml},0.05\mathrm{M} ? \end{gathered}$$

no. of moles of CuSO₄=$\frac{\mathrm{M}\times \mathrm{V}\left(\mathrm{ml}\right)}{1000}=\frac{0.05\times 100}{1000}=0.005\mathrm{moles}$

Amount of 'Cu' formed= 0.005mol=0.005$\times$63.54= 0.3177 g.