Zinc reacts with hydrochloric acid to give hydrogen and zinc chloride. The volume of hydrogen gas produced at STP from the reaction of 11.5 g of zinc with excess HCl is _____ L (Nearest integer)
(Given: Molar mass of Zn is $65.4 {gmol}^{- 1}$ and Molar volume of H₂ at STP=22.7 L)

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answer is 4.

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Detailed Solution

$\begin{array}{l} Zn + 2 HCl \to {ZnCl}_{2} + H_{2} \\ 65.4 g Zn = 22.7 L \\ Volume occupies by 11.5 g of Zn = \frac{11.5 g}{65.4 g} \times 22.4 L \\ = 3.98 L ≅ 4 L \end{array}$

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