Zinc reacts with ${\displaystyle CuS{O}_4}$ according to the equation ${\displaystyle Zn+CuS{O}_4\to ZnS{O}_4+Cu}$. If excess of zinc is added to 100ml of 0.05M ${\displaystyle CuS{O}_4}$, the amount of copper formed

$$\begin{gathered} \mathrm{Zn}+\underset{100\mathrm{ml} 0.05\mathrm{M}}{{\mathrm{CuSO}}_4}\to {\mathrm{ZnSO}}_4+\mathrm{Cu} \\ \mathrm{M}=\frac{\mathrm{n}\times 1000}{\mathrm{V}\left(\mathrm{ml}\right)}\Rightarrow \mathrm{n}=\frac{0.05\mathrm{M}\times 100}{1000}=5\times {10}^{-3} \mathrm{mol} \\ 1\mathrm{mol} \mathrm{of} {\mathrm{CuSO}}_4 \to 63.54\mathrm{g} \mathrm{Cu} \\ 5\times {10}^{-3}\mathrm{mol} \mathrm{of} {\mathrm{CuSO}}_4\to ? \\ \mathrm{Amount} \mathrm{of} \text{'}\mathrm{Cu}\text{'} \mathrm{formed}=63.54\times 5\times {10}^{-3}=0.3177\mathrm{g} \end{gathered}$$