Zn(OH)2 is an amphoteric hydroxide and is involved in the following two equilibria in aqueous solutions.Zn(OH)2(s)⇌Zn2+(aq)+2OH−(aq);Ksp=1.2×10−17Zn(OH)2(s)+2OH−(aq)⇌[Zn(OH)4]2−(aq);Kc=0.12At what pH the solubility of Zn(OH)2 be minimum? If your answer is X then given the value of X2 .

S=Ksp[OH−]2+Kc.[OH−]2 For minimum solubility d[S]d[OH−]=0 −2Ksp[OH−1]3+2Kc[OH−]=0 KspKc=[OH−1]4 [OH−]=10−4H+=10−10pH=10

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$Z n {(O H)}_{2}$ is an amphoteric hydroxide and is involved in the following two equilibria in aqueous solutions.
$\begin{array}{l} Z n {(O H)}_{2} (s) ⇌ Z n^{2 +} (a q) + 2 O H^{-} (a q); K_{s p} = 1.2 \times 10^{- 17} \\ Z n {(O H)}_{2} (s) + 2 O H^{-} (a q) ⇌ {[Z n {(O H)}_{4}]}^{2 -} (a q); K_{c} = 0.12 \end{array}$
At what pH the solubility of $Z n {(O H)}_{2}$ be minimum? If your answer is X then given the value of $\frac{X}{2}$ .

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answer is 5.

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Detailed Solution

$S = \frac{K s p}{{[O H^{-}]}^{2}} + K_{c} . {[O H^{-}]}^{2} F o r m i n i m u m s o l u b i l i t y \frac{d [S]}{d [O H^{-}]} = 0 \frac{- 2 K_{s p}}{{[O H^{- 1}]}^{3}} + 2 K_{c} [O H^{-}] = 0 \frac{K_{s p}}{K_{c}} = {[O H^{- 1}]}^{4} [O H^{-}] = 10^{- 4} H^{+} = 10^{- 10} p H = 10$

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