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Q.

z=x+iy and w=1izzi, then |w|=1In the complex plane

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a

z lies on the imaginary axis

b

z lies on the parabola

c

z lies on the unit circle

d

z lies on the real axis

answer is B.

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Detailed Solution

Wi=z+izi|z+i|=|zi|
z lies on perpendicular bisector of (0, –1) and (0, 1) i.e. x axis (Real axis)

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z=x+iy and w=1−izz−i, then |w|=1⇒In the complex plane