Q.

In the Calvin cycle, for the fixation of 1 molecule of CO2, how many ATP and NADPH+H+ molecules are required in the reduction step?

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18 ATP and 12 NADPH+H+

2 ATP and 2 NADPH+H+

10 ATP and 10 NADPH+H+

3 ATP and 2 NADPH+H+

answer is 2.

(Detailed Solution Below)

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Detailed Solution

In one turn of Calvin cycle, 2 molecules of 3-PGA are formed. Each molecule of 3-PGA is reduced to PGAL using 1 ATP and 1 NADPH+H+ molecule. Therefore, 2 ATP and 2 NADPH+H+ are required to reduce 2 molecules of 3-PGA formed during fixation of 1 molecule of CO2.

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