A DNA molecule has 100 bp. The number of adenine residues in it is 40. Calculate the total number of hydrogen bonds present in the DNA.

DNA molecule has 100bp= 200 nucleotides.No. of adenine residues= 40Therefore, no. of thymine residues= 40Total no. of guanine and cytosine present= 200-(40+40) = 120No. of cytosine= No. of guanine= 120/2= 602 hydrogen bonds between A and T and 3 hydrogen bonds between G and CTotal no. of hydrogen bond= (60*3) + (40*2) = 260