A heterozygous individual $$++/ab$$ is crossed to its recessive parent and has produced the offsprings in following proportion $$++/ab$$ – $$200a+/ab$$ – $$50+b/ab$$ – $$30ab/ab$$ – $$100What$$ is the expected distance between the two gene loci?

Question

A heterozygous individual $$++/ab$$ is crossed to its recessive parent and has produced the offsprings in following proportion $$++/ab$$ – $$200a+/ab$$ – $$50+b/ab$$ – $$30ab/ab$$ – $$100What$$ is the expected distance between the two gene loci?

Infinity Learn · Accepted Answer

When a heterozygous individual $$++/ab$$ is crossed to its recessive parent, the offspring with the following genotypes are formed.Parental genotypes $$-$$ $$++/ab$$ – $$200Recombinant$$ genotypes $$-$$ $$a+/ab$$ – $$50Recombinant$$ genotypes $$-$$ $$+b/ab$$ – $$30Parental$$ genotypes $$-$$ $$ab/ab$$ – $$100Recombination$$ frequency $$=$$  Number of recombinants (80)Total$$ number of off $$spring(380) X $$100$$ $$=$$ $$21$$ % Distance between gene a and gene b is $$21cM$$.

A heterozygous individual ++/ab is crossed to its recessive parent and has produced the offsprings in following proportion
++/ab – 200
a+/ab – 50
+b/ab – 30
ab/ab – 100
What is the expected distance between the two gene loci?

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A heterozygous individual ++/ab is crossed to its recessive parent and has produced the offsprings in following proportion ++/ab – 200a+/ab – 50+b/ab – 30ab/ab – 100What is the expected distance between the two gene loci?

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Ready to Test Your Skills?

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A heterozygous individual ++/ab is crossed to its recessive parent and has produced the offsprings in following proportion
++/ab – 200
a+/ab – 50
+b/ab – 30
ab/ab – 100
What is the expected distance between the two gene loci?