Identify the correct statement with respect to genetic code.
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a
60 codons of genetic code, code for amino acids and 4 codons do not code for any amino acid.
b
All the terminating codons start with the nucleotide U
c
2 nucleotides make one codon
d
AUG and AAU code for methionine
answer is B.
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Detailed Solution
UAG, UGA, UAA are stop codons61 codons code for 20 amino acids and 3 codons do not code for any amino acid.3 nucleotides make one codon.AUG codes for methionine. It is unique codon. AAU code for amino acid Asparagine.