If E. coli having heavy DNA was allowed to grow for 80 minutes on a medium containing 14NH4Cl then what would be the proportions of light and hybrid densities DNA molecule?
80minutes= 80/20= 4 generations
Initially DNA contain 15N15N
Then it is placed in a medium containing 14N for 3 generation.
After 1st generation:
15N15N→ 15N14N 15N14N (2 Hybrid DNA molecules)
After 2nd generation
15N14N 15N14N → 15N14N 14N14N 15N14N 14N14N (2 light DNA and 2 Hybrid DNA molecules)
After 3rd generation:
15N14N 14N14N 15N14N 14N14N → 15N14N 14N14N 14N14N 14N14N 15N14N 14N14N 14N14N 14N14N (6 light DNA and 2 hybrid DNA molecules)
After 4th generation
2(15N14N) → 2 (15N14N 14N14N)
6(14N14N) → 6 (14N14N 14N14N)
Total no. of light DNA= 14
Total no. of Hybrid DNA= 2
% of light DNA= 87.5%
% of light DNA= 12.5%
Talk to our academic expert!
Similar Questions
DNA replication is semiconservative. It was shown first in
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests