If a pea plant produces 1616 plants in F2 generation with respect to dihybrid cross for seed color and shape, how many of them have parental genotypes?

In F2 generation the probability of formation of dominant parent with genotype RR YY is 116 and another parent with rr yy genotype also there is formation of 116. The sum of these probabilities is 116+116 = 18. The number of plants formed with the genotype of parents would be 16168 = 202.