First slide

Inheritance of Two Genes

Question

If a pea plant produces 1616 plants in $F_{2}$ generation with respect to dihybrid cross for seed color and shape, how many of them have parental genotypes?

Easy

A

202
B

101
C

404
D

1010

Solution

In $F_{2}$ generation the probability of formation of dominant parent with genotype RR YY is $\frac{1}{16}$ and another parent with rr yy genotype also there is formation of $\frac{1}{16}$ . The sum of these probabilities is $\frac{1}{16} + \frac{1}{16} = \frac{1}{8}$ . The number of plants formed with the genotype of parents would be $\frac{1616}{8} = 202$ .

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