Questions
If pea plant produces 2560 seeds in generation when a dihybrid cross is done between homozygous Round and Yellow seeded plant and wrinkled and green seeded plant, how many of them have the phenotype wrinkled yellow seeds?
detailed solution
Correct option is C
The phenotypic ratio of F2 generation Round Yellow 9 : Round green 3 : wrinkled yellow 3 : wrinkled green 1. Hence the number of wrinkled yellow seeded plants would be 2560 × 316 = 480.Talk to our academic expert!
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