If there are $$999$$ bases in an RNA that code for a protein with $$333$$ amino acids, and the base at position $$901$$ is deleted such that the length of the RNA becomes $$998$$ bases, how many codons will be altered?

Question

Infinity Learn · Accepted Answer

RNA of $$999$$ bases gives rise to protein made up of $$333$$ amino acids because each  code is of triplet nature. If $$901$$ position base removed than rest of the frame of $$m-RNA$$ genetic code will get altered. So after $$900th$$ base rest of genetic code will change that means $$33$$  codes will be altered while $$300$$ codons which are present before the base at $$901$$ position remain the same.

If there are 999 bases in an RNA that code for a protein with 333 amino acids, and the base at position 901 is deleted such that the length of the RNA becomes 998 bases, how many codons will be altered?

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