If there are 999 bases in an RNA that code for a protein with 333 amino acids, and the base at position 901 is deleted such that the length of the RNA becomes 998 bases, how many codons will be altered?

RNA of 999 bases gives rise to protein made up of 333 amino acids because each  code is of triplet nature. If 901 position base removed than rest of the frame of m-RNA genetic code will get altered. So after 900th base rest of genetic code will change that means 33  codes will be altered while 300 codons which are present before the base at 901 position remain the same.