Individuals homozygous for linked ‘p’ and 'q' genes were crossed with wild type (+ +). The F1 hybrid thus produced was test crossed. It produced the progeny in the following proportion:++=800pq= 900+p= 100+q= 200Calculate the distance between p and q genes present on the same chromosome.
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a
20 map units
b
15 map units
c
10 map units
d
30 map units
answer is B.
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Detailed Solution
Number of Recombinant= 100+200=300Total number of offspring= 800+900+100+200= 2000Distance between p and q genes = (300/2000) x100 = 15 map units