Individuals homozygous for linked ‘p’ and 'q' genes were crossed with wild type (+ +). The hybrid thus produced was test crossed. It produced the progeny in the following proportion:
++=800
pq= 900
+p= 100
+q= 200
Calculate the distance between p and q genes present on the same chromosome.
Number of Recombinant= 100+200=300
Total number of offspring= 800+900+100+200= 2000
Distance between p and q genes = (300/2000) x100 = 15 map units