Q.
Individuals homozygous for linked ‘p’ and 'q' genes were crossed with wild type (+ +). The F1 hybrid thus produced was test crossed. It produced the progeny in the following proportion:++=800pq= 900+p= 100+q= 200Calculate the distance between p and q genes present on the same chromosome.
see full answer
Start JEE / NEET / Foundation preparation at rupees 99/day !!
21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya
a
20 map units
b
15 map units
c
10 map units
d
30 map units
answer is B.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Number of Recombinant= 100+200=300Total number of offspring= 800+900+100+200= 2000Distance between p and q genes = (300/2000) x100 = 15 map units
Watch 3-min video & get full concept clarity