A man with genotype EEFfGg can produce a P number of genetically different sperms and women with genotype LLMmNn can produce a Q number of genetically different eggs. Determine the values of P and Q.

The man has 2 heterozygous condition in the genotype. Therefore, the number of gametes produced is 2n. i.e., 22=4. Therefore, P is 4. The woman also has 2 heterozygous condition in the genotype. Therefore, the number of gametes produced is 2n, i.e., 22=4. therefore, Q=4.