Number of cells participating during double fertilization are
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a
Five
b
Four
c
Three
d
Two
answer is B.
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Detailed Solution
Double fertilization = Syngamy + Triple fusionDuring syngamy, one male gamete cell (n) will fuse with egg cell (n) to form zygote.During triple fusion, one male gamete (n) fuse with two polar nuclei (n+n) in central cell to form primary endosperm cell (3n; PEC). Therefore, in all four cells participates in double fertilization.