Two parenchyma cells P and Q are present adjacent to each other. Cell P has osmotic potential of - 2 pascals and pressure potential of 0.25 pascals. Cell Q has osmotic potential of - 5 pascals and pressure potential of 4 pascals. The result will be

The water potential of cell P = - 2 + 0.25 = - 1.75The water potential of cell Q = - 5 + 4 = - 1Cell P has less water potential and cell Q has high water potential.Water moves from a cell of high water potential to a cell of low water potential. Hence water moves from Q to P.