At 87∘Cthe following equilibrium is established. H2(g)+S(s)⇌H2S(g);Kc=0.08If 0.3 mole hydrogen and 2 mole sulphur are heated to 87oC in a 2 L vessel, what will be the concentration of H2S at equilibrium?

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0.011M

0.022 M

0.044 M

0.08 M

answer is B.

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Detailed Solution

Kc=H2 S(g)H2(g) ⇒8×10-2=x0.3-x ⇒ x=0.022 H2 S(g)=0.0222 =0.011M

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