∆G in Joules for the conversion of 0.9 g of water at 100°C and 1 atm to steam at 100°C and 0.5 atm pressure is ______.

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answer is -107.5.

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Detailed Solution

The process may be broken into two steps:Step I: water at 100°C, 1 atm → steam at 100°C, 0.5 atm;ΔG=nRTln⁡P2P1 Hence, ΔG=ΔG1+ΔG2=0+(−107.5)=−107.5J

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