First slide
Enthalpy of Atomisation and bond dissociation
Question

HCO , HO=O , HC=O respectively are 1070, 498 and 741KJ/mol. Then ΔH for CO+12O2CO2[in KJ] is

Moderate
Solution

\begin{array}{l} {\Delta _r}{H^o} = B{E_{C \equiv O}} + \frac{1}{2}B{E_{O = O}}[ - 2B{E_{C = O}}]\\\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\, = \,1070 + {\textstyle{{498} \over 2}} - [2 \times 741]\\\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\, = - 163KJ\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\, \end{array}

 

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