1×10-3m solution of PtNH32Cl4 in H2O shows depression in freezing point by 0.0054oC. The ionisable Cl- ions will be (Given,Kf(H2O)=1.860 K kg mno-1)

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answer is B.

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Detailed Solution

ΔTf=iKfm⇒0.0054=i×1.86×0.001i=5.41.86≈3PtNH32Cl2Cl2⇌PtNH32Cl22++2Cl−So, ionisable Cl- ions ate 2.

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