Q.

6.02×1020 molecules of urea are present in 100 mL of its solution. The concentration of solution is

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a

0.02

b

0.01

c

0.001

d

0.1

answer is B.

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Detailed Solution

Given, number of molecules of urea = 6.02×1020∴Number of moles = 6.02×1020NA=6.02×10206.023×1023 =1×10-3 molVolume of the solution =100 mL=1001000 L=0.1 LConcentration of urea solution  (in molL-1 ) =1×10-30.1=mol L-1=1×10-2 mol L-1=0.01 mol L-1
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