Q.

6.02×1020 molecules of urea are present in 200 mL of its solution. The concentration of urea solution is (N0=6.02×1023mol-1)

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

0.001 M

b

0.01 M

c

0.005 M

d

0.10 M

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Molarity (mol L-1)=Moles of soluteVolume of solution (in L)6.02×1023 molecules of urea = 1 mole ∴6.02×1020 molecules of urea =6.02×10206.02×1023=1×10-3mol200 ml = 0.20 LMolarity =1×10-30.20=0.005M
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon