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Q.

6.02  ×  1020 molecules of urea are present in 100 mL solution. The concentration of urea solution is

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a

0.1 M

b

0.01 M

c

0.02 M

d

0.001 M

answer is B.

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Detailed Solution

M=Moles  of  ureaV in  litre=6.02  ×  1020  ×  10006.23  ×  1023  ×  100=10−2 M
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