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AB2 is 10% dissociated in water to A2+ and B− the boiling point of a 10.0 molal aqueous solution of AB2 is ……….. .°C (Round off to the Nearest Integer).[ Given: Molal elevation constant of water Kb=0.5Kkg mol-1boiling point of pure water =100°C

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answer is 106.

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Detailed Solution

Given α=0.1,n=3α=i−1n−1⇒i=1.2ΔTb=1.2×0.5×10=6 B.P of solution =100+6=1060C

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