First slide

Kohlraush law

Question

According to Kohlrausch law, the limiting value of molar conductivity of an electrolyte A₂B is

Easy

A

$\large \lambda _{{A^ + }}^\infty \, + \,\lambda _{{B^{ - 2}}}^\infty$
B

$\frac{1}{2}\lambda _{{A^ + }}^\infty \, + \,\lambda _{{B^{ - 2}}}^\infty$
C

$2\lambda _{{A^ + }}^\infty \, + \,\frac{1}{2}\,\lambda _{{B^{ - 2}}}^\infty$
D

$2\lambda _{{A^ + }}^\infty \, + \,\,\lambda _{{B^{ - 2}}}^\infty$

Solution

For electrolyte of type
${A_x}{B_y} \rightleftharpoons x{A^{ + y}} + y{B^{ - x}}$

$\lambda _{m({A_x}{B_y})}^o = x\lambda _{m\left( {{A^{ + y}}} \right)}^o + y\lambda _{m\left( {{B^{ - x}}} \right)}^o$

${A_2}B \rightleftharpoons 2{A^ + } + {B^{ - 2}}$

$\lambda _{{A_2}B}^m = 2\lambda _{{A^ + }}^m + \lambda _{{B^{ - 2}}}^m$

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