Q.

According to MO theory,

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a

O2+is paramagnetic and bond order greater than O2

b

O2+is paramagnetic and bond order less than O2

c

O2+is diamagnetic and bond order is less than O2

d

O2+is diamagnetic and bond order is more than O2

answer is A.

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Detailed Solution

In O2 molecule, the total number of electrons = 16Electronic distribution in molecular orbital of O2=σ1s2,σ∗1s2,σ2s2,σ∗2s2,σ2px2π2py2,π2pz2 , π∗2py1,∗2pz1 Bond order in O2=12Nb−Na=12[10−6]=2.0 In O2+=σ1s2,∗1s2,σ2s2,σ∗2s2,σ2px2π2py2=π2pz2, ∗2py1 Bond order in O2+=Nb−Na2=10−52=2.5
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According to MO theory,