1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
O2+is paramagnetic and bond order greater than O2
b
O2+is paramagnetic and bond order less than O2
c
O2+is diamagnetic and bond order is less than O2
d
O2+is diamagnetic and bond order is more than O2
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
In O2 molecule, the total number of electrons = 16Electronic distribution in molecular orbital of O2=σ1s2,σ∗1s2,σ2s2,σ∗2s2,σ2px2π2py2,π2pz2 , π∗2py1,∗2pz1 Bond order in O2=12Nb−Na=12[10−6]=2.0 In O2+=σ1s2,∗1s2,σ2s2,σ∗2s2,σ2px2π2py2=π2pz2, ∗2py1 Bond order in O2+=Nb−Na2=10−52=2.5