Questions

According to MOT, O-O bond order in $O_{2}^{-}$ is equal to

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ctaimg

a

1

b

2

c

2.5

d

1.5

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detailed solution

Correct option is D

O2-2-KK'σ2s2σ2s*2σ2pz2π2px2π2py2π2px*2π2py*2O2--KK'σ2s2σ 2s*2σ2pz2π2py2π2py2π2px*2π2py*1O2 -KK'σ2s2σ2s*2σ2pz2π2px2π2py2π2px*1π2py*1O2+-KK'σ2s2σ2s*2σ2pz2π2px2π2py2π2px*1π2py*0Bond order and magnetic moment :μs=nn+2 B. M ; O2-2=10-82=1; Diamagnetic...μs=0 ; O2-=10-72=1.5; Paramagnetic..μs=1.732 B.M ; O2=10-62=2; Paramagnetic.......μs=2.82 B.M ; O2+=10-52=2.5; Paramagnetic.....μs=1.732B.M ;O — O bond length inO2-2>O2->O2>O2+

ctaimg

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Similar Questions

The increasing order of energies of various molecular orbitals are

$I. σ 1 s < σ^{*} 1 s < σ 2 s < σ^{*} 2 s < σ 2 p_{z} <$ $(π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ^{*} 2 p_{z}$

$II. σ 1 s < σ^{*} 1 s < σ 2 s < σ^{*} 2 s < (π 2 p_{x} = π 2 p_{y})$ $< σ 2 p_{z} < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ^{*} 2 p_{z}$

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