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In acidic medium, the rate of reaction between ${({BrO}_{3})}^{-}$ and ${Br}^{-}$ ions is given by the expression.
$- [d ({BrO}_{3}^{-}) / dt] = K [{BrO}_{3}^{-}] [{Br}^{-}] {[H^{+}]}^{2}$ It means:

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Rate constant of overall reaction is 4 sec⁡−1

Rate of reaction is independent of the concentration of acid

The changes in pH of the solution will not affect the rate

Doubling the concentration of H+ ions will increase the reaction rate by 4 times.

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detailed solution

Correct option is D

−d[BrO3−]dt=k[BrO3−][Br−][H+]2So, on doubling the concentration of H+ ion will increase the reaction rate by 4 times.

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In acidic medium, the rate of reaction between (BrO3)− and Br− ions is given by the expression. −[d(BrO3−)/dt]=K[BrO3−][Br−][H+]2 It means:

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Ready to Test Your Skills?

free study material

In acidic medium, the rate of reaction between ${({BrO}_{3})}^{-}$ and ${Br}^{-}$ ions is given by the expression.
$- [d ({BrO}_{3}^{-}) / dt] = K [{BrO}_{3}^{-}] [{Br}^{-}] {[H^{+}]}^{2}$ It means: