Q.

In an acidified solution of K2Cr2O7,H2O2 is added. Then,

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a

solution turns green due to formation of Cr2O3

b

solution turns yellow due to formation of K2CrO4

c

a blue coloured compound CrO(O2)2 is formed

d

Solution gives green precipitate of Cr(OH)3

answer is C.

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Detailed Solution

Hydrogen peroxide acts as an oxidising as well as a reducing agent in both acidic and alkaline media. When H2O2 is added to an acidified potassium dichromate solution, the blue coloured compound CrO5 or CrO(O2)2 is formed. The chemical reaction is as followsCr2O72−+2H++4H2O2→2CrOO22+5H2O
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