The activation energy for a hypothetical reaction, A→product , is 12.49 kcal/mole . If temperature is raised from 295 to 305, the rate of reaction increased by
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a
60%
b
100%
c
50%
d
20%
answer is B.
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Detailed Solution
logr2r1=Ea2.303R1T1-1T2logr2r1=12.49×10002.303×2×1295-1305 =0.30138=log2 r2=2r1So rate increases by 100%