Q.

The activation energy of a reaction is 58.3 kJ / mole. The ratio of the rate constants at 305K and 300K is about (R = 8.3Jk-1mol-1) (Antilog 0.1667 = 1.468)

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a

1.25

b

1.75

c

1.5

d

2.0

answer is C.

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Detailed Solution

T1 = 300 KT2 = 305 KR = 8.314 J K-1 mole-1 = 8.314 x 10-3 KJ K-1 mole-1Ea = 58.3 KJ/mole
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The activation energy of a reaction is 58.3 kJ / mole. The ratio of the rate constants at 305K and 300K is about (R = 8.3Jk-1mol-1) (Antilog 0.1667 = 1.468)