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Q.

The activation energy of a reaction is 58.3 kJ/mole. The ratio of the rate constants at 300C and 270C is about (R=8.3Jk−1mol−1)  [ log(1.26)=0.10066 ]

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a

1.26

b

0.63

c

6.3

d

2.52

answer is A.

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Detailed Solution

logk2k1=Ea2.303R[T2−T1T1×T2] logk2k1=58.3×10002.303×8.31300-1303= - 0.1006k1k2=1.26
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