Q.

The active mass of 64 g of HI in a 2L flask would be

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a

0.25 mol/L

b

0.50 mol/L

c

0.025 mol/L

d

32.0 mol/L

answer is A.

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Detailed Solution

Moles of HI=64128 (Molar mass of HI=1+127=128 g mol-1Active mass is moles per litre[HI]=641282=0.25 mol/L
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