The active mass of 64 g of HI in a two litre flask would be

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0.25

answer is D.

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Detailed Solution

Active mass = conc.(nv)HI → 1 +127 = 128 g/mol No. of moles(wtmwt) =64128=0.5 mol conc.(nv )=0.5 mol2 L=0.25 mol/L

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