Addition of excess aqueous ammonia to a pink coloured aqueous solution of MCl2.6H2O (X) and NH4Cl gives an octahedral complex Y in the presence of air. In aqueous solution, complex Y behaves as 1: 3 electrolyte. The reaction of X with excess HCl at room temperature results in the formation of a blue coloured complex Z. The calculated spin only magnetic moment of X and Z is 3.87 B.M., whereas it is zero for complex Y.
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a
The hybridization of the central metal ion in Y is d2sp3
b
When X and Z are in equilibrium at 0°C , the colour of the solution is pink
c
Z is a tetrahedral complex
d
Addition of silver nitrate to Y gives only two equivalent of silver chloride
answer is A.
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Detailed Solution
X→CoH2O6Cl2→pink→sp3d2 Y→CoNH36Cl3→d2sp3 Z→CoCl4→blue→sp3Option (B) is correct due to equilibrium.Hence ‘A’ is correctZ is tetrahedral , ‘C’ is correct