Addition of 0.643 g of a compound to 50 ml of benzene (density = 0.879 g mol-1) lowers the freezing point from 50.51oC to 50.03oC. If Kf for benzene is 5.12, the molecular mass of the compound is

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156.00

312.00

78.00

468.000

answer is A.

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Detailed Solution

Weight of benzene =V×d=50×0.879 gW=43.95 gWeight of compound = 0.643 gmΔTf=50.51−50.03=0.48∴ ΔTf=Kf×wm×1000w0.48=5.12×0.643m×100043.95∴ m=156.05 gr

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